document.write( "Question 166748: 5(5)^-.08x=6 \n" ); document.write( "
Algebra.Com's Answer #122878 by nerdybill(7384)\"\" \"About 
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Hey, this sounds familiar...
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\n" ); document.write( "When you posted:
\n" ); document.write( "5(5)^-0.08x=6
\n" ); document.write( "I assume you mean:
\n" ); document.write( "5(5)^(-0.08x)=6
\n" ); document.write( "This means 5 is raised to the power of (-0.08x)
\n" ); document.write( "If this is incorrect, please write back
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\n" ); document.write( "If so, start by dividing both sides by 5:
\n" ); document.write( "(5)^(-0.08x)=6/5
\n" ); document.write( "(5)^(-0.08x)=1.2
\n" ); document.write( "Take the LOG5 of both sides:
\n" ); document.write( "-0.08x = LOG5(1.2)
\n" ); document.write( "-0.08x = LOG(1.2)/LOG(5)
\n" ); document.write( "-0.08x = .0792/.6990
\n" ); document.write( "-0.08x = .1133
\n" ); document.write( "x = -1.416 \n" ); document.write( "
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