document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=166759>Question 166759</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Order of operations.  Im a father with a question on this... (8-5x) (3x+2) When x=4 When the numbers inside are found. do you Multiply the two numbers?? giving the answer -168? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122872 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (8-5x) (3x+2) When x=4 When the numbers inside are found. do you Multiply the two numbers?? giving the answer -168?<BR>\n" );
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document.write( "Substitute 4 for x.  5x means 5 times x, so that's 20<BR>\n" );
document.write( "(8-5x) (3x+2) = (8-20)*(12+2)<BR>\n" );
document.write( "= -12*14<BR>\n" );
document.write( "= -168\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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