document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=166724>Question 166724</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Charlie owns a coffee shop. He wants to create special mixes using 2 coffees,one priced at $6.40 per pound and the other priced at $7.28 per pound.  How many pounds of the $7.28 coffee should he mix with 9 pounds of the $6.40 coffee to sell the mixture for $6.95 per pound? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122862 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122862\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     Charlie owns a coffee shop. He wants to create special mixes using 2 coffees,one priced at $6.40 per pound and the other priced at $7.28 per pound. How many pounds of the $7.28 coffee should he mix with 9 pounds of the $6.40 coffee to sell the mixture for $6.95 per pound?<BR>\n" );
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document.write( "Let x = pounds of $7.28 per pound coffee added<BR>\n" );
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document.write( "7.28x + 6.40(9) = 6.95(x+9)<BR>\n" );
document.write( "7.28x + 57.6 = 6.95x + 62.55<BR>\n" );
document.write( "0.33x + 57.6 = 62.55<BR>\n" );
document.write( "0.33x = 4.95<BR>\n" );
document.write( "x = 15 pounds  (of $7.28 coffee)<BR>\n" );
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