document.write( "Question 166678: When the digits of a two-digit number are reversed, the new nwmber is 9 more than the original number, and the sum of the digits of the original number is 11.What is the original number? \n" ); document.write( "
Algebra.Com's Answer #122843 by ankor@dixie-net.com(22740)\"\" \"About 
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When the digits of a two-digit number are reversed, the new number is 9 more
\n" ); document.write( " than the original number, and the sum of the digits of the original number
\n" ); document.write( "is 11. What is the original number?
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\n" ); document.write( "Write the two digit number as: (10x + y); where x=10's digit and y=units digit
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\n" ); document.write( "\"When the digits of a two-digit number are reversed, the new number is 9 more than the original number,\"
\n" ); document.write( "(10y+x) = (10x+y) + 9
\n" ); document.write( "10y - y = 10x - x + 9
\n" ); document.write( "9y = 9x + 9
\n" ); document.write( "Simplify, divide equation by 9
\n" ); document.write( "y = x + 1
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\n" ); document.write( " and the sum of the digits of the original number is 11.
\n" ); document.write( "x + y = 11
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\n" ); document.write( "What is the original number?
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\n" ); document.write( "Substitute (x+1) for y in the above equation
\n" ); document.write( "x + (x+1) = 11
\n" ); document.write( "2x = 11 - 1
\n" ); document.write( "2x = 10
\n" ); document.write( " x = 5, then obviously y = 6
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\n" ); document.write( "The number is: 56
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\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "\"When the digits of a two-digit number are reversed, the new number is 9 more than the original number,\"
\n" ); document.write( "65 = 56 + 9 \n" ); document.write( "
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