document.write( "Question 166664: addition method
\n" ); document.write( " 4x-2y=5
\n" ); document.write( "24x-9y=-3
\n" ); document.write( "by what constant should one of the eauations be multiplied if the x terms are to drop out? \n" ); document.write( "

Algebra.Com's Answer #122829 by jim_thompson5910(35256) $\"\"$ $\"About$

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Notice how the x coefficients are 4 and 24. Also, notice how the LCM of 4 and 24 is 24. This means that we must multiply 4 by 6 to get to the LCM 24. Now the goal is to make the x coefficients equal but have an opposite sign. \r
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\n" ); document.write( "\n" ); document.write( "So if we multiply the first equation by -6 (to make the first coefficient negative), we'll get $\"-24x%2B12y=-30\"$ which when added to $\"24x-9y=-3\"$ we'll get $\"-24x%2B24x%2B12y-9y=-30-3\"$ which becomes $\"3y=-33\"$ . \n" ); document.write( "

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