document.write( "Question 166605: Write the equation of a quadratic that has zeros of 5 and 1 with F(0)=1. I understand you need to multiply (x-5)(x-1) to get the polynomial, but f(0) wouldnt equal 1. PLEASE HELP ME OUT!!! \n" ); document.write( "

Algebra.Com's Answer #122797 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
You are absolutely correct in what you have said!
\n" ); document.write( "If x = 5 and x = 1 are zeros of the quadratic equation then (x-5) and (x-1) are factors, so their product will give you the equation:
\n" ); document.write( " $\"%28x-5%29%28x-1%29+=+x%5E2-6x-5\"$
\n" ); document.write( "So that you would have:
\n" ); document.write( " $\"f%28x%29+=+x%5E2-6x%2B5\"$ and, of course:
\n" ); document.write( " $\"f%280%29+=+0-0%2B5\"$
\n" ); document.write( " $\"f%280%29+=+5\"$ Not 1!
\n" ); document.write( "But, I'm wondering if something didn't get turned around here and what was really intended was:
\n" ); document.write( " $\"f%281%29+=+0\"$ ...and this is certainly true! \n" ); document.write( "

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