document.write( "Question 166582: Rental Company A charges $12.00 plus 80 cents per hour to rent a paint sprayer. A competitor, Rental company B rents the same sprayer for $3.95 plus $1.50 per hour.\r
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document.write( "Write an algebraic equation for the cost in terms of the number of hours rented for each business.\r
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document.write( "Determine algebraically the number of hours for which the cost of renting a paint sprayer will be the same for company A or B. \n" );
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Algebra.Com's Answer #122767 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Rental Company A charges $12.00 plus 80 cents per hour to rent a paint sprayer. A competitor, Rental company B rents the same sprayer for $3.95 plus $1.50 per hour. \n" ); document.write( "Write an algebraic equation for the cost in terms of the number of hours rented for each business. \n" ); document.write( "Determine algebraically the number of hours for which the cost of renting a paint sprayer will be the same for company A or B \n" ); document.write( ". \n" ); document.write( "Let h = number of hours rented \n" ); document.write( ". \n" ); document.write( "Company A: \n" ); document.write( "C(h) = 12 + .80h \n" ); document.write( ". \n" ); document.write( "Company B: \n" ); document.write( "C(h) = 3.95 + 1.50h \n" ); document.write( ". \n" ); document.write( "To find out when the cost will be the same, set it equal to each other and solve for 'h': \n" ); document.write( "12 + .80h = 3.95 + 1.50h \n" ); document.write( "12 = 3.95 + .70h \n" ); document.write( "8.05 = .70h \n" ); document.write( "11.5 hours = h \n" ); document.write( " \n" ); document.write( " |