document.write( "Question 166415: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? \n" ); document.write( "
Algebra.Com's Answer #122766 by ankor@dixie-net.com(22740)\"\" \"About 
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Two cyclists start biking from a trail's start 3 hours apart. The second cyclist
\n" ); document.write( " travels at 10 miles per hour and starts 3 hours after the first cyclist who is
\n" ); document.write( "traveling at 6 miles per hour. How much time will pass before the second cyclist
\n" ); document.write( " catches up with the first from the time the second cyclist started biking?
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\n" ); document.write( "Let t = travel time of the 2nd cyclist (10 mph)
\n" ); document.write( "then
\n" ); document.write( "(t+3) = travel time of the 1st cyclist (6 mph)
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\n" ); document.write( "When the 2nd cyclist catches up with the 1st they will have traveled the same distance
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\n" ); document.write( "Write a distance equation using this fact: (Dist = speed * time)
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\n" ); document.write( "10s = 6(s+3)
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\n" ); document.write( "10s = 6s + 18
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\n" ); document.write( "10s - 6s = 18
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\n" ); document.write( "4s = 18
\n" ); document.write( "s = \"18%2F4\"
\n" ); document.write( "s = 4.5 hrs travel time of the 2nd cyclist
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\n" ); document.write( "Check solution by confirming they traveled the same distance
\n" ); document.write( "7.5 * 6 = 45 mi
\n" ); document.write( "4.5 * 10 = 45 mi \n" ); document.write( "
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