document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=166542>Question 166542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can someone please show me how to do this problem:\r<BR>\n" );
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document.write( "Find the value(s) of the function, subject to the system of inequalities.\r<BR>\n" );
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document.write( "Find the minimum of P = 23x + 21y + 22 subject to:\r<BR>\n" );
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document.write( "x (greater than or equal to) 0, y ( greater than or equal to) 0, x + y (greater than or equal to) 1.\r<BR>\n" );
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document.write( "a. 66<BR>\n" );
document.write( "b. 43<BR>\n" );
document.write( "c. 45<BR>\n" );
document.write( "d. 22 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122758 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122758\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> your constraints are:<BR>\n" );
document.write( "x >= 0<BR>\n" );
document.write( "y >= 0<BR>\n" );
document.write( "x+y >=1<BR>\n" );
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document.write( "since the equation is 23*x and 21*y, you want to make x = 0 which will be the smallest term you can use for x or y.<BR>\n" );
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document.write( "if you make x = 0, then x + y >=1 becomes y >= 1 which means you want to make y = 1 because 1 is the smallest it can become.<BR>\n" );
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document.write( "assuming x = 0 and y = 1, the results of the equation become:<BR>\n" );
document.write( "23*0 + 21*1 + 22 = 43.<BR>\n" );
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document.write( "the smallest value of your equation is 43 which is option b.<BR>\n" );
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document.write( "if you had made y = 0, then x would have had to have been 1, and your equation would have become:<BR>\n" );
document.write( "23*1 + 21*0 + 22 = 45<BR>\n" );
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document.write( "option b is your answer and the values you had to use are:<BR>\n" );
document.write( "x = 0<BR>\n" );
document.write( "y = 1<BR>\n" );
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