document.write( "Question 166425: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? \n" ); document.write( "
Algebra.Com's Answer #122754 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "so lets call d1=r1*T1 1st cyclist T1=T+3 r1=6 \n" ); document.write( ".............d2=r2*T2 2nd cyclist T2=T r2=10 \n" ); document.write( ": \n" ); document.write( "d1 has to equal d2 since they travel the same distance. \n" ); document.write( ": \n" ); document.write( "equations: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and since: \n" ); document.write( "\n" ); document.write( "then: \n" ); document.write( ": \n" ); document.write( "2nd cyclist was cycling \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |