document.write( "Question 166524: when angelo burnini rows his gondola in still water(with no current) in venice,italy, he travels at 3 mph. when he rows at the same rate in the grand canal, it takes him the same amount of time to travel 2.4 miles downstream (with the current) as it does to travel 2.3 miles upstream (against the current). find the current of the river. \n" ); document.write( "
Algebra.Com's Answer #122748 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let r=speed of the current
\n" ); document.write( "Time to travel upstream=2.3/(3-r) (Note: Upstream we have to subtract the speed of the current; downstream, we add)
\n" ); document.write( "Time to travel downstream=2.4/(3+r)\r
\n" ); document.write( "\n" ); document.write( "Now we are told that the above two times are equal, so:
\n" ); document.write( "2.3/(3-r)=2.4/(3+r) multiply each side by (3-r)(3+r) (or cross multiply)
\n" ); document.write( "2.3(3+r)=2.4(3-r) get rid of parens (distributive law)
\n" ); document.write( "6.9+2.3r=7.2-2.4r subtract 6.9 from and add 2.4r to each side
\n" ); document.write( "6.9-6.9+2.3r+2.4r=7.2-6.9-2.4r+2.4r collect like terms\r
\n" ); document.write( "\n" ); document.write( "4.7r=0.3 divide each side by 4.7
\n" ); document.write( "r=0.0638 mph -----------------------speed of the current\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "2.3/(3-0.0638)=2.4/(3+0.0638)
\n" ); document.write( "0.783=0.783\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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