document.write( "Question 166465: Mike can travel 120 miles by car in the same amount of time he can take the train 150 miles. if the train travels 10 miles faster than the car, find the speed of the car and the speed of the train.\r
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Algebra.Com's Answer #122741 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let r=rate (speed) of the car
\n" ); document.write( "Then r+10=rate of the train\r
\n" ); document.write( "\n" ); document.write( "Time travelling by car=120/r
\n" ); document.write( "Time travelling by train=150/(r+10)
\n" ); document.write( "Now we are told that the above two times are equal. so:
\n" ); document.write( "120/r=150/(r+10) multiply each term by r(r+10) (or cross multiply)
\n" ); document.write( "120(r+10)=150r get rid of parens (distributive law)
\n" ); document.write( "120r+1200=150r subtract 120r from each side
\n" ); document.write( "120r-120r+1200=150r-120r collect like terms
\n" ); document.write( "30r=1200 divide each side by 30
\n" ); document.write( "r=40 mph----------------------------speed of the car
\n" ); document.write( "r+10=40+10=50 mph--------------------speed of the train\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "120/40=150/50
\n" ); document.write( "3=3\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "

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