document.write( "Question 166495: State the number of positive real zeros, negative real zeros, and imaginary zeros for g(x)=9x^3-7x^2+10x-4.
\n" ); document.write( "I must show my work. This is from a worksheet and I'm not sure how to do it.
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Algebra.Com's Answer #122721 by stanbon(75887)\"\" \"About 
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State the number of positive real zeros, negative real zeros, and imaginary zeros for
\n" ); document.write( "g(x)=9x^3-7x^2+10x-4.
\n" ); document.write( "g(-x) = -9x^2 - 7x^2 - 10x -4
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\n" ); document.write( "Using DesCartes Rule of Signs:
\n" ); document.write( "# of changes of sign in g(x) = 3; so 1 or 3 positive Real roots
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\n" ); document.write( "# of changes of sign in g(-x) = 0; so 0 negative Real Roots
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\n" ); document.write( "# of imaginary zeroes is 0 or two because g(x) is a cubic
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\n" ); document.write( "Comment: graphing g(x) is find it has one positive Real Root.
\n" ); document.write( "So it must have 2 imaginary roots.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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