document.write( "Question 166509: a picture is 1 inch longer than it is wide. it is put into a frame one half inch wider on every side. find the area of the picture if the frame area is eight inches squared. \n" ); document.write( "
Algebra.Com's Answer #122717 by ankor@dixie-net.com(22740)\"\" \"About 
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a picture is 1 inch longer than it is wide. it is put into a frame one half inch wider on every side. find the area of the picture if the frame area is eight inches squared.
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\n" ); document.write( "Let x = width of the picture
\n" ); document.write( "then
\n" ); document.write( "(x+1) = length of the picture
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\n" ); document.write( "Frame 1/2 inch wider all around, therefore
\n" ); document.write( "x + 2(.5)=
\n" ); document.write( "(x+1) = width of the frame
\n" ); document.write( "and
\n" ); document.write( "(x+1) + 2(.5) =
\n" ); document.write( "x + 1 + 1 =
\n" ); document.write( "(x+2) = length of the the frame
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\n" ); document.write( "Frame area given as 8 sq/in, therefore
\n" ); document.write( "(x+1)*(x+2) = 8
\n" ); document.write( "FOIL
\n" ); document.write( "x^2 + 3x + 2 = 8
\n" ); document.write( "x^2 + 3x + 2 - 8 = 0
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\n" ); document.write( "a quadratic equation
\n" ); document.write( "x^2 + 3x - 6 = 0
\n" ); document.write( "Use the quadratic formula to find x: a=1; b=3; c=-6
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\n" ); document.write( "You should get a positive solution about x = 1.37 inches is the width of the pic
\n" ); document.write( "then, 2.37 = length
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\n" ); document.write( "A = 1.37 * 2.37
\n" ); document.write( "A = 3.25 sq/in is the picture
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\n" ); document.write( "Check solution: Frame dimensions 2.37 by 3.37
\n" ); document.write( "Frame area = 2.37 * 3.37 = 7.77 ~ 8 sq/in as given\r
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