document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2837>Question 2837</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the information about a pair of similar solids to find all possible values of x:\r<BR>\n" );
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document.write( "Scale factor is 1:2; Volume ration is x-2:x^2-1  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1227 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1227\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  For the two similar solids, the scalar  factor 1:2 means their ratio in<BR>\n" );
document.write( " length. Hence, their ratio in volume should be 1^3:2^3 = 1:8.\r<BR>\n" );
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document.write( " Now, we have  (x-2):(x^2-1) = 1:8,<BR>\n" );
document.write( " So, x^2-1 = 8(x-2), or  x^2- 8x + 15 = 0.\r<BR>\n" );
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document.write( " Factoring (x-3)(x-5) = 0, we have x=3 or 5.\r<BR>\n" );
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document.write( " Kenny<BR>\n" );
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