document.write( "Question 166491: please help me solve\r
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document.write( "1) 6x^2+24x=2x^2-36\r
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document.write( "2) 3x^2-17x+20=0
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document.write( "for this one i got (x-6)(3x-5)
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document.write( "is this correct\r
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document.write( "3) x^2-36=0 \n" );
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Algebra.Com's Answer #122698 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1) 6x^2+24x=2x^2-36 \n" ); document.write( "4x^2 +24x + 36 = 0 \n" ); document.write( "x^2 + 6x + 9 = 0 \n" ); document.write( "(x+3)^2 = 0 \n" ); document.write( "x = -3 with multiplicity 2 \n" ); document.write( "=================================== \n" ); document.write( "2) 3x^2-17x+20=0 \n" ); document.write( "3x^2 - 12x - -5x + 20 = 0 \n" ); document.write( "3x(x-4)-5(x-4) = 0 \n" ); document.write( "(x-4)(3x-5) = 0 \n" ); document.write( "x = 4 or x = 5/3 \n" ); document.write( "=====================\r \n" ); document.write( "\n" ); document.write( "3) x^2-36=0 \n" ); document.write( "(x-6)(x+6) = 0 \n" ); document.write( "x = 6 or x = -6 \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |