document.write( "Question 166487: The perimeter of a rectangle is 46m. If the width were doubled and the length were increased by 6 m, the perimeter would be 70 m. What are the length and width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #122686 by nerdybill(7384)\"\" \"About 
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The perimeter of a rectangle is 46m. If the width were doubled and the length were increased by 6 m, the perimeter would be 70 m. What are the length and width of the rectangle?
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\n" ); document.write( "Let x = width
\n" ); document.write( "and y = length
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\n" ); document.write( "Since we have two unknowns, we'll need two equations.
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\n" ); document.write( "perimeter of any rectangle = 2(width + length)
\n" ); document.write( "2(x+y) = 46
\n" ); document.write( "2x+2y = 46 (equation 1)
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\n" ); document.write( "2(2x + y+6) = 70
\n" ); document.write( "4x+2y+12 = 70
\n" ); document.write( "4x+2y = 58 (equation 2)
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\n" ); document.write( "Using the \"elimination method\" we subtract equation 1 from 2:
\n" ); document.write( "4x+2y = 58
\n" ); document.write( "-2x-2y = -46
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\n" ); document.write( "2x = 12
\n" ); document.write( "x = 6 m
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\n" ); document.write( "Substitute the above into equation 1 and solve for y:
\n" ); document.write( "2x+2y = 46
\n" ); document.write( "2(6)+2y = 46
\n" ); document.write( "12+2y = 46
\n" ); document.write( "2y = 34
\n" ); document.write( "y = 17 m
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\n" ); document.write( "solution:
\n" ); document.write( "width is 6 m
\n" ); document.write( "length is 17 m
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