document.write( "Question 166460: What number does the t stand for in each of the following equations:
\n" ); document.write( "a. 100=125-5t squared
\n" ); document.write( "b. 50=125-5t squared
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Algebra.Com's Answer #122672 by jim_thompson5910(35256)\"\" \"About 
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I'll do the first one to get you started\r
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\n" ); document.write( "\n" ); document.write( "a)\r
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\n" ); document.write( "\n" ); document.write( "\"100=125-5t%5E2\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"0=125-5t%5E2-100\" Subtract 100 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"0%2B5t%5E2=125-100\" Add \"5t%5E2\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"5t%5E2=25\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"t%5E2=%2825%29%2F%285%29\" Divide both sides by \"5\".\r
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\n" ); document.write( "\n" ); document.write( "\"t%5E2=5\" Divide.\r
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\n" ); document.write( "\n" ); document.write( "\"t=0%2B-sqrt%285%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"t=sqrt%285%29\" or \"t=-sqrt%285%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"t=sqrt%285%29\" or \"t=-sqrt%285%29\".
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