document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=166438>Question 166438</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the absolute value inequality. Other than Ø, use interval notation to express the solution set and graph the solution set on a number line.\r<BR>\n" );
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document.write( "|2y + 6/3 - 9| < 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122667 by </B><A HREF=/tutors/aboutme.mpl?userid=Personal+Trainer+DC><B>Personal Trainer DC(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Personal+Trainer+DC><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122667\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since it's an absolute value, you need to re-write the inequality considering the negative and positive side:\r<BR>\n" );
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document.write( "-2 < 2y + 6/3 - 9 < 2\r<BR>\n" );
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document.write( "Then, add 9 to both sides:\r<BR>\n" );
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document.write( "7 < 2y + 6/3 < 11\r<BR>\n" );
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document.write( "Then, subtract 6/3 (ie. 2) from both sides:\r<BR>\n" );
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document.write( "5 < 2y < 9\r<BR>\n" );
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document.write( "Then, divide by 2:\r<BR>\n" );
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document.write( "5/2 < y < 9/2\r<BR>\n" );
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document.write( "In interval notation, (5/2, 9/2) </SPAN>\n" );
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