document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=166446>Question 166446</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0131482874/algebrahomeworkh>Beginning Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I caanot for the life of me figure out how to solve this problem. We are asked to collect the variable terms on the left side of the inequality.\r<BR>\n" );
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document.write( "0.2(3-x)+0.1>0.1(x-2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122661 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122661\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> collect the variable terms on the left side of the inequality. <BR>\n" );
document.write( "0.2(3-x)+0.1>0.1(x-2)<BR>\n" );
document.write( "--------------------------<BR>\n" );
document.write( "Multiply both sides of the inequality by 10 to get:\r<BR>\n" );
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document.write( "2(3-x) + 1 > 1(x-2)<BR>\n" );
document.write( "6-2x + 1 > x-2<BR>\n" );
document.write( "-3x+7 > -3<BR>\n" );
document.write( "-3x > -10<BR>\n" );
document.write( "=============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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