document.write( "Question 166429: A cyclist traveled at a rate of 32 mph to visit a nearby town. They cyclist averaged 10 mph on the return trip. If the round trip took 6.3 hours, find the distance to the nearby town. \n" ); document.write( "
Algebra.Com's Answer #122652 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
distance going call d1
\n" ); document.write( "distance returning call d2
\n" ); document.write( "d1=d2
\n" ); document.write( "time returning call t
\n" ); document.write( "time going call t-6.3
\n" ); document.write( "rate going is 32mph
\n" ); document.write( "rate returning is 10mph\r
\n" ); document.write( "\n" ); document.write( "d1=32(6.3-t)
\n" ); document.write( "d2=10t\r
\n" ); document.write( "\n" ); document.write( "32(6.3-t)=10t
\n" ); document.write( "201.6-32t=10t
\n" ); document.write( "42t=201.6
\n" ); document.write( "t=4.8
\n" ); document.write( "so \"d=10%284.8%29=48miles\"
\n" ); document.write( "
\n" ); document.write( "
\n" );