document.write( "Question 166424: x+2y =4
\n" ); document.write( "3x-2y =6
\n" ); document.write( "Solve by substitution \n" ); document.write( "

Algebra.Com's Answer #122649 by MRperkins(300) $\"\"$ $\"About$

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$\"x%2B2y=4\"$
\n" ); document.write( " $\"3x-2y=6\"$
\n" ); document.write( ".
\n" ); document.write( "in order to substitute, you need to find out what one variable is equal to.
\n" ); document.write( "In this case it is easiest to get x by itself with the first equation by subtracting 2y from each side. When you do this, you get: $\"x=-2y%2B4\"$
\n" ); document.write( "now you substitute this into the other equation.
\n" ); document.write( " $\"3%28-2y%2B4%29-2y=6\"$
\n" ); document.write( ".
\n" ); document.write( "distribute the 3
\n" ); document.write( " $\"-6y%2B12-2y=6\"$
\n" ); document.write( ".
\n" ); document.write( "combine like terms
\n" ); document.write( " $\"-8y%2B12=6\"$
\n" ); document.write( ".
\n" ); document.write( "subtract 12 from each side
\n" ); document.write( " $\"-8y=-6\"$
\n" ); document.write( ".
\n" ); document.write( "divide each side by -8
\n" ); document.write( " $\"y=3%2F4\"$
\n" ); document.write( ".
\n" ); document.write( "now plug this into the first equation to find out what x is:
\n" ); document.write( " $\"x=-2%283%2F4%29%2B4\"$
\n" ); document.write( " $\"x=2.5\"$
\n" ); document.write( ".
\n" ); document.write( "so: $\"x=2.5\"$ ; $\"y=3%2F4\"$
\n" ); document.write( ".
\n" ); document.write( "Plug these values in to the original equation to check for accuracy.
\n" ); document.write( ".
\n" ); document.write( "If you want your questions answered quickly and consistently then consider making me your private tutor. For more information click on my name to go to my website or email me @ justin.sheppard.tech@hotmail.com \n" ); document.write( "

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