document.write( "Question 166394: Please help me with the following question:
\n" ); document.write( "Find an equation of variation where y varies jointly as x and z and inversely as the square of w and y=20 when x=-0.5, z=4, and w=5.
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Algebra.Com's Answer #122644 by gonzo(654)\"\" \"About 
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y varies jointly as x and z means y = k*x*z (equation 1)
\n" ); document.write( "y varies inversely as square of w means y = k/w^2 (equation 2)
\n" ); document.write( "y varies jointly as x and z, and inversely as w^2 means y = k*x*z/w^2 (equation 3)
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\n" ); document.write( "given y = 20 when x = -.5, z = 4, and w = 5
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\n" ); document.write( "plug these into equation 3
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\n" ); document.write( "20 = k*((-.5)*(4))/(5^2)
\n" ); document.write( "simplify:
\n" ); document.write( "20 = -2*k/25
\n" ); document.write( "multiply both sides of equation by 25
\n" ); document.write( "25*20 = -2*k
\n" ); document.write( "simplify
\n" ); document.write( "500 = -2*k
\n" ); document.write( "divide both sides of equation by 2
\n" ); document.write( "250 = -k
\n" ); document.write( "multiply botrh sides of equation by -1
\n" ); document.write( "-250 = k
\n" ); document.write( "which is the same as
\n" ); document.write( "k = -250
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\n" ); document.write( "now that you have k, plug it back into the equation to see that it is correct.
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\n" ); document.write( "20 = [-250*(-.5)*(4)]/25
\n" ); document.write( "20 = [-250*(-2)]/25
\n" ); document.write( "20 = 500/25
\n" ); document.write( "20 = 20
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\n" ); document.write( "this is how it works:
\n" ); document.write( "k = constant of proportionality.
\n" ); document.write( "if y varies directly with x, then y = k*x
\n" ); document.write( "if y varies directly ,and jointly, with x and z, then y = k*x*z
\n" ); document.write( "if y varies inversely with x, then y = k/x
\n" ); document.write( "if y varies inversely with x^2, then y = k/x^2
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