document.write( "Question 166395: Can someone please help me with the following question:
\n" ); document.write( "The current I in electrical conductor varies inversely as the resistance R of the conductor. Suppose I is 0.2 amperes when the resistance is 200 ohms. Find the current when the resistance is 250 ohms. \n" ); document.write( "

Algebra.Com's Answer #122622 by Mathtut(3670) $\"\"$ $\"About$

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when you have and inverse relation as opposed to a direct proportion it means that as one thing increases the other decreases or vise versa. so in a direct relationship y directly related to x for instance you have a \r
\n" ); document.write( "\n" ); document.write( "relationship of y/x=k but in an inverse relationship y inversely related to x the y*x=k so in our problem I*R=k in this case\r
\n" ); document.write( "\n" ); document.write( "(.2)200=40 now we are asked to find I when R=250 so I(250) must equal our constant number which is 40 so I(250)=40 divide by 250 and you get .16\r
\n" ); document.write( "\n" ); document.write( "an other way of doing this is to put the ratio of I/I2=R2/R \r
\n" ); document.write( "\n" ); document.write( "so (.2)/I=250/200 $\"I=.16\"$ \n" ); document.write( "

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