document.write( "Question 166338: i would like to correct my submisson i meant to type\r
\n" ); document.write( "\n" ); document.write( "2zx to the second power times y=18 where x=1,z=y
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Algebra.Com's Answer #122605 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2zx%5E2y=18\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"2y%281%29%5E2%28y%29=18\" Plug in x=1 and z=y\r
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\n" ); document.write( "\n" ); document.write( "\"2y%2A%28y%29=18\" Square 1 to get 1 and multiply\r
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\n" ); document.write( "\n" ); document.write( "\"2y%5E2=18\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2=9\" Divide both sides by 2\r
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\n" ); document.write( "\n" ); document.write( "\"y=3\" or \"y=-3\" Take the square root of both sides (don't forget the negative answer)\r
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\n" ); document.write( "\n" ); document.write( "So when x=1 and z=y, then \"y=3\" or \"y=-3\"
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