document.write( "Question 166325: I am very interested in how one would derive a quadratic equation from a physical parabola. I have one that measures 3.5\" from vertex to \"mouth\" and 4.5\" across the \"mouth.\" I plotted it on a graph with a y intercept of 3.5 and x intercepts of 2.25, -2.25. I played with your quadratic solver and a graphing calculator and the closest I was able to come to was \"-.691x%5E2%2B3.5=0\". How could I solve this without using the aforementioned tools?\r
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Algebra.Com's Answer #122589 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Center your parabola at (0,0).
\n" ); document.write( "Then the general equation of the parabola becomes
\n" ); document.write( "\"y=ax%5E2\"
\n" ); document.write( "From your measurement, at x=2.25, y=3.5,
\n" ); document.write( "\"y=ax%5E2\"
\n" ); document.write( "\"3.5=a%282.25%29%5E2\"
\n" ); document.write( "\"a=3.5%2F%282.25%29%5E2\"
\n" ); document.write( "\"a=3.5%2F5.0625\"
\n" ); document.write( "\"a=0.6914\"
\n" ); document.write( "a is the same, the other constant just scales the graph with regards to the origin.
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