document.write( "Question 166315: the odds in favor of Trudy beating her friend in a round of golf are 1:9. Find the probability that Trudy will lose. \n" ); document.write( "
Algebra.Com's Answer #122572 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! the odds in favor of Trudy beating her friend in a round of golf are 1:9. Find the probability that Trudy will lose. \n" ); document.write( "----------- \n" ); document.write( "Formula: \"odds FOR event A\" = P(A)/P(not A) \n" ); document.write( "-------- \n" ); document.write( "Your Problem: \n" ); document.write( "1:9 = P(A)/P(not A) \n" ); document.write( "P(A) = (1/9)*P(not A) \n" ); document.write( "---------- \n" ); document.write( "But P(A) + P(not A) = 1 \n" ); document.write( "So, P(not A) = 1 - P(A) \n" ); document.write( "And P(not A) = 1 - [(1/9)P(not A)] \n" ); document.write( "(10/9)P(not A) = 1 \n" ); document.write( "P(not A) = 9/10\r \n" ); document.write( "\n" ); document.write( "======================= \n" ); document.write( "That was a bit long-winded. Here's a shorter version. \n" ); document.write( "Since odds FOR = 1:9 \n" ); document.write( "P(A) = 1/(1+9) = 1/10 \n" ); document.write( "So P(A') = 9/10 \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |