document.write( "Question 166305: Solve using the square root property:
\n" ); document.write( "(x + 6)2 = 121
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Algebra.Com's Answer #122567 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B6%29%5E2=121\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B6=0%2B-sqrt%28121%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B6=sqrt%28121%29\" or \"x%2B6=-sqrt%28121%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B6=11\" or \"x%2B6=-11\" Take the square root of \"121\" to get \"11\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=-6%2B11\" or \"x=-6-11\" Subtract \"6\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=5\" or \"x=-17\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=5\" or \"x=-17\".
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