document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=166299>Question 166299</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y varies directly with x if y=16 when x=48<BR>\n" );
document.write( "A: find the constant of variation,k, and write an equation for the direct variation.<BR>\n" );
document.write( "B: find x when y=-27 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122560 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122560\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in  direct proportions if y varies directly with x then 16/48=1/3\r<BR>\n" );
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document.write( "1. so the constant k is 1/3 and all y/x terms must be in that proportion\r<BR>\n" );
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document.write( "2.so 16/48=-27/x   so 16x=-27(48)---->16x=-1296 so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=-81 ALIGN=MIDDLE  ALT=\"x=-81\"   DISABLED_style= \"max-width:90%; height:auto;\" >   you will see that if you take -27/-81 you will have a 1/3 ratio if you simplify </SPAN>\n" );
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