document.write( "Question 166270This question is from textbook Algebra and Trigonometry Structure and Method book 2
\n" ); document.write( ": I have been working on this math problem and I can't figure it out. I was wondering if someone could help me? Please and Thank You!!! I would deeply appreciate it!!\r
\n" ); document.write( "\n" ); document.write( "Factoring Quadratic Polynomials
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Algebra.Com's Answer #122536 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E6-64y%5E6\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E3%29%5E2-64y%5E6\" Rewrite \"x%5E6\" as \"%28x%5E3%29%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E3%29%5E2-%288y%5E3%29%5E2\" Rewrite \"64y%5E6\" as \"%288y%5E3%29%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "Notice how we have a difference of squares. So let's use the difference of squares formula \"A%5E2-B%5E2=%28A%2BB%29%28A-B%29\" to factor the expression:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E3%2B8y%5E3%29%28x%5E3-8y%5E3%29\" Factor the expression using the difference of squares.\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"x%5E3%2B8y%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3%2B8y%5E3\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%29%5E3%2B%282y%29%5E3\" Rewrite \"x%5E3\" as \"%28x%29%5E3\". Rewrite \"8y%5E3\" as \"%282y%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B2y%29%28%28x%29%5E2-%28x%29%282y%29%2B%282y%29%5E2%29\" Now factor by using the sum of cubes formula. Remember the sum of cubes formula is \"A%5E3%2BB%5E3=%28A%2BB%29%28A%5E2-AB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B2y%29%28x%5E2-2xy%2B4y%5E2%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E3%2B8y%5E3\" factors to \"%28x%2B2y%29%28x%5E2-2xy%2B4y%5E2%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E3%2B8y%5E3=%28x%2B2y%29%28x%5E2-2xy%2B4y%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's factor \"x%5E3-8y%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3-8y%5E3\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%29%5E3-%282y%29%5E3\" Rewrite \"x%5E3\" as \"%28x%29%5E3\". Rewrite \"8y%5E3\" as \"%282y%29%5E3\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2y%29%28%28x%29%5E2%2B%28x%29%282y%29%2B%282y%29%5E2%29\" Now factor by using the difference of cubes formula. Remember the difference of cubes formula is \"A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2y%29%28x%5E2%2B2xy%2B4y%5E2%29\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E3-8y%5E3\" factors to \"%28x-2y%29%28x%5E2%2B2xy%2B4y%5E2%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E3-8y%5E3=%28x-2y%29%28x%5E2%2B2xy%2B4y%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E6-64y%5E6\" completely factors to \"%28x%2B2y%29%28x-2y%29%28x%5E2-2xy%2B4y%5E2%29%28x%5E2%2B2xy%2B4y%5E2%29\" (I just rearranged the factors a bit)\r
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\n" ); document.write( "\n" ); document.write( "Note: the order of the factors does not matter
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