document.write( "Question 166269: the sum of two odd integers whose sum is 48 \n" ); document.write( "
Algebra.Com's Answer #122535 by jim_thompson5910(35256)\"\" \"About 
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Odd integers follow the pattern \"2x%2B1\", \"2x%2B3\", etc\r
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\n" ); document.write( "\n" ); document.write( "So if the \"sum of two odd integers whose sum is 48\" then \"%282x%2B1%29%2B%282x%2B3%29=48\"\r
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\n" ); document.write( "\n" ); document.write( "\"4x%2B4=48\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"4x=48-4\" Subtract \"4\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"4x=44\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2844%29%2F%284%29\" Divide both sides by \"4\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=11\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=11\" which means that the two numbers are \"2%2811%29%2B1=23\" and \"2%2811%29%2B3=25\"
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