document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=166247>Question 166247</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a certain fraction, the denominator is 4 less than the numerator. If 3 is added to both the numerator and the denominator, the resulting fraction is equal to 5/7. What was the orginal fraction? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122520 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+3)/(x-4+3)=5/7<BR>\n" );
document.write( "(x+3)/(x-1)=5/7<BR>\n" );
document.write( "7(x+3)=5(x-1)<BR>\n" );
document.write( "7x+21=5x-5<BR>\n" );
document.write( "7x-5x=-5-21<BR>\n" );
document.write( "2x=-26<BR>\n" );
document.write( "x=-26/2<BR>\n" );
document.write( "x=-13<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "(-13+3)/(-13-4+3)=5/7<BR>\n" );
document.write( "-10/-14=5/7<BR>\n" );
document.write( "5/7=5/7\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );