document.write( "Question 166246: A rancher bought some calves for $170. \"Jet Age\" rustlers stole 6 of them. Four months later, the rancher sold the remaining calves for $240 each. He paid a feed bill of $400 and still made a profit of $4110. How many calves did he buy? \n" ); document.write( "
Algebra.Com's Answer #122518 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! hmmmm.\r \n" ); document.write( "\n" ); document.write( "well it should be money recieved-costs=profit\r \n" ); document.write( "\n" ); document.write( "money received would be (x-6)240 where x is the original amount of calves \n" ); document.write( "costs equals 170+400=570 \n" ); document.write( "profit equals 4110\r \n" ); document.write( "\n" ); document.write( "so that would be (x-6)240-570=4110 \n" ); document.write( " 240x-1440-570=4110 \n" ); document.write( " 240x=6120 \n" ); document.write( " \n" ); document.write( "but that is what I come up with rounded to nearest 1 would be 26 calves \n" ); document.write( " |