document.write( "Question 166246: A rancher bought some calves for $170. \"Jet Age\" rustlers stole 6 of them. Four months later, the rancher sold the remaining calves for $240 each. He paid a feed bill of $400 and still made a profit of $4110. How many calves did he buy? \n" ); document.write( "
Algebra.Com's Answer #122518 by Mathtut(3670)\"\" \"About 
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hmmmm.\r
\n" ); document.write( "\n" ); document.write( "well it should be money recieved-costs=profit\r
\n" ); document.write( "\n" ); document.write( "money received would be (x-6)240 where x is the original amount of calves
\n" ); document.write( "costs equals 170+400=570
\n" ); document.write( "profit equals 4110\r
\n" ); document.write( "\n" ); document.write( "so that would be (x-6)240-570=4110
\n" ); document.write( " 240x-1440-570=4110
\n" ); document.write( " 240x=6120
\n" ); document.write( " \"x=25.5\" which is the part that doesnt make much sense
\n" ); document.write( "but that is what I come up with rounded to nearest 1 would be 26 calves
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