document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=166202>Question 166202</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a plane which can fly 520mph in still air flies for 3 hours against a wind and for 2 hours with the same wind. The total distance it covers is 2565 miles. find rate of the wind. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122495 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122495\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> lets call s the rate of the plane which is 520mph d=2565\r<BR>\n" );
document.write( "\n" );
document.write( "now with the formula distance(d)=rate*time or d=rt lets break this trip down into 2 segments. We will call the speed of the wind w.\r<BR>\n" );
document.write( "\n" );
document.write( "d=(s-w)3+(s+w)2---->2565=(520-w)3+(520+w)2--->2565=1560-3w+1040+2w \r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w=35 ALIGN=MIDDLE  ALT=\"w=35\"   DISABLED_style= \"max-width:90%; height:auto;\" > after combining like terms and solving for w.\r<BR>\n" );
document.write( "\n" );
document.write( "so the rate of the wind <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=35mph ALIGN=MIDDLE  ALT=\"35mph\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );