document.write( "Question 166192: 2. Biologists want to set up a station to test alligators in the lake for West Nile Virus. Suppose that the costs for such a station are $2,500 for setup costs and $3.00 to administer each test. \r
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document.write( "a. Write an expression that gives the total cost to test x animals.\r
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document.write( "b. You can find the average cost per animal by dividing total costs by number of animals. Write the expression that gives the average cost per animal.\r
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document.write( "c. Find the average cost per animal for 10 animals. 100 animals. 1,000 animals.\r
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document.write( "d. As the number of animals tested increases, what happens to the average cost to test the animals? Would the average cost ever fall below $3.00? If so, identify a value that supports your answer. If not, explain how you know. \r
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document.write( "e. How many animals should be tested for the average cost to be $5.00 per animal? \r
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Algebra.Com's Answer #122475 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! OK we are given fixed cost of 2500. Lets call total cost C and the number of animals A. We are given an additional cost of $3.00 for each test administered to an animal.\r \n" ); document.write( "\n" ); document.write( "a. so to express total cost to test A animals we have \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b. Average cost per animal would be total cost divided by total number of animals \n" ); document.write( "\n" ); document.write( "c For 10 animals we have (2500+3(10)/10= $253/animal \n" ); document.write( " For 100 animals we have (2500+3(100)/100= $28/animal \n" ); document.write( " For 1000 animals we have (2500+3(1000)/1000= $5.4/animal \r \n" ); document.write( "\n" ); document.write( "d. the avg cost per animal decreases as the amount of animals increases.\r \n" ); document.write( "\n" ); document.write( " the avg cost per animal will never go below 3--->avg cost =(2500+3A)/A \n" ); document.write( " or (2500/A)+3 so it can get close to $3/animal but never quite reachs it. \n" ); document.write( "e (2500+3A)/A=5 so 2A=2500 A=1250 animals to avg $5 in costs \n" ); document.write( " |