document.write( "Question 166033: 36.) If a manufacturer charges q dollars each for footballs, then he can sell 3000 - 150q footballs per week. Find a polynomial R(q) that represents the revenue for one week. Find the weekly revenue if the price is $8 for each football.\r
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document.write( "This is the answer that it is showing r(q)= -150q^2 + 3000q, 14,400
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document.write( "Can you show me how they got this answer please. \n" );
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Algebra.Com's Answer #122472 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! This football problem has been kicking around for few days. \n" ); document.write( ": \n" ); document.write( "If a manufacturer charges q dollars each for footballs, then he can sell 3000 - 150q footballs per week. Find a polynomial R(q) that represents the revenue for one week. \n" ); document.write( ": \n" ); document.write( "Revenue = price times number sold (q=price), (number sold = 3000-150q) \n" ); document.write( "R(q) = q(3000-150q) \n" ); document.write( "; \n" ); document.write( "Multiply what's inside the brackets \n" ); document.write( "R(q) = 3000q - 150q^2 \n" ); document.write( "or \n" ); document.write( "R(q) = -150q^2 + 3000q \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Find the weekly revenue if the price is $8 for each football. \n" ); document.write( ": \n" ); document.write( "Take the above equation, substitute 8 for q and find R(q) \n" ); document.write( "R(q) = -150(8^2) + 3000(8) \n" ); document.write( ": \n" ); document.write( "R(q) = -150(64) + 24000 \n" ); document.write( ": \n" ); document.write( "R(q) = -9600 + 24000 \n" ); document.write( ": \n" ); document.write( "R(q) = $14,400 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Did this explain it to you? \n" ); document.write( " |