document.write( "Question 166033: 36.) If a manufacturer charges q dollars each for footballs, then he can sell 3000 - 150q footballs per week. Find a polynomial R(q) that represents the revenue for one week. Find the weekly revenue if the price is $8 for each football.\r
\n" ); document.write( "\n" ); document.write( "This is the answer that it is showing r(q)= -150q^2 + 3000q, 14,400
\n" ); document.write( "Can you show me how they got this answer please.
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Algebra.Com's Answer #122472 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
This football problem has been kicking around for few days.
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\n" ); document.write( "If a manufacturer charges q dollars each for footballs, then he can sell 3000 - 150q footballs per week. Find a polynomial R(q) that represents the revenue for one week.
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\n" ); document.write( "Revenue = price times number sold (q=price), (number sold = 3000-150q)
\n" ); document.write( "R(q) = q(3000-150q)
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\n" ); document.write( "Multiply what's inside the brackets
\n" ); document.write( "R(q) = 3000q - 150q^2
\n" ); document.write( "or
\n" ); document.write( "R(q) = -150q^2 + 3000q
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\n" ); document.write( "Find the weekly revenue if the price is $8 for each football.
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\n" ); document.write( "Take the above equation, substitute 8 for q and find R(q)
\n" ); document.write( "R(q) = -150(8^2) + 3000(8)
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\n" ); document.write( "R(q) = -150(64) + 24000
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\n" ); document.write( "R(q) = -9600 + 24000
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\n" ); document.write( "R(q) = $14,400
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\n" ); document.write( "Did this explain it to you?
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