document.write( "Question 166189: I need to answer this question using quadratics and I am not sure where to start. Ed needs to enclose a rectangular section of his yard. The area is 35 sq ft and the perimeter is 27 ft. Find the length and the width of the section. \n" ); document.write( "
Algebra.Com's Answer #122455 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! since A=lw where l is length and w is the width \n" ); document.write( "and P=2(l+w)\r \n" ); document.write( "\n" ); document.write( "we plug in the known values\r \n" ); document.write( "\n" ); document.write( "35=lw \n" ); document.write( "27=2(l+w)--->27/2=l+w---->l=27/2-w---->l=(27-2w)/2\r \n" ); document.write( "\n" ); document.write( "place value of l into 1st equation----->35=((27-2w)/2)(w)-----> \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when w=7/2 l=10 when w=10 l=7/2 |