document.write( "Question 166189: I need to answer this question using quadratics and I am not sure where to start. Ed needs to enclose a rectangular section of his yard. The area is 35 sq ft and the perimeter is 27 ft. Find the length and the width of the section. \n" ); document.write( "
Algebra.Com's Answer #122455 by Mathtut(3670)\"\" \"About 
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since A=lw where l is length and w is the width
\n" ); document.write( "and P=2(l+w)\r
\n" ); document.write( "\n" ); document.write( "we plug in the known values\r
\n" ); document.write( "\n" ); document.write( "35=lw
\n" ); document.write( "27=2(l+w)--->27/2=l+w---->l=27/2-w---->l=(27-2w)/2\r
\n" ); document.write( "\n" ); document.write( "place value of l into 1st equation----->35=((27-2w)/2)(w)----->\"70=27w-2w%5E2\"
\n" ); document.write( "\"2w%5E2-27w%2B70=0\" factoring (2w-7)(w-10) so w=7/2,10\r
\n" ); document.write( "\n" ); document.write( "when w=7/2 l=10 when w=10 l=7/2 \"width=+%287%2F2%29+length=+%2810%29\"
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