document.write( "Question 166180: I'm not sure if this is the right section, but I will still ask.
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document.write( "1. Use synthetic division to find f(-3) for f(x)2x^3-6x^2-5x+7.
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document.write( "2. One factor of f(x)=x^3+x^2-22x-40 is x+4. Find the other factors.
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document.write( "I must show my work and have no textbook to explain. Will you PLEASE HELP!!!!
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document.write( "Thanks \n" );
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Algebra.Com's Answer #122454 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! 1. You don't need synthetic division to find f(-3). Just substitute. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "2. Here you need the synthetic division. \n" ); document.write( "Showing synthetic division is a little difficult. \n" ); document.write( "The first part will show the factor (left hand column), then the factor times the divisor, \n" ); document.write( "then the next line will show the subtraction. \n" ); document.write( "Repeat. \n" ); document.write( "Hopefully it makes sense. \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "..........._______________ \n" ); document.write( "(x+4)|x^3+x^2-22x-40 \n" ); document.write( "x^2:...x^3+4x^2 \n" ); document.write( "..................-3x^2-22x-40 \n" ); document.write( "-3x:..........-3x^2-12x \n" ); document.write( ".............................-10x-40 \n" ); document.write( "-10:......................-10x-40\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Now you can factor the quadratic, \n" ); document.write( " \n" ); document.write( "and substitute back, \n" ); document.write( " |