document.write( "Question 166073: question 1) A sailboat travels 20 miles downstream in 3 hours. It returns in 4 hours. Find the speed of the sailboat in still water and the rate of the current.\r
\n" ); document.write( "\n" ); document.write( "question 2) Erin's age is 3 times Warren's. In 4 years she will be twice as old as he will be. How old is each now.
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Algebra.Com's Answer #122420 by midwood_trail(310)\"\" \"About 
You can put this solution on YOUR website!
I will do question only.\r
\n" ); document.write( "\n" ); document.write( "(2) Erin's age is 3 times Warren's. In 4 years she will be twice as old as he will be. How old is each now.\r
\n" ); document.write( "\n" ); document.write( "I will do question (2) first.\r
\n" ); document.write( "\n" ); document.write( "Warren's age now is x.\r
\n" ); document.write( "\n" ); document.write( "Erin's age now is 3x.\r
\n" ); document.write( "\n" ); document.write( "In 4 years, they both will be 4 years older, right?\r
\n" ); document.write( "\n" ); document.write( "3x + 4 = Erin's age 4 years form now.\r
\n" ); document.write( "\n" ); document.write( "x + 4 = Warren's age 4 years from now.\r
\n" ); document.write( "\n" ); document.write( "3x + 4 = 2(x + 4)\r
\n" ); document.write( "\n" ); document.write( "3x + 4 = 2x + 8\r
\n" ); document.write( "\n" ); document.write( "3x - 2x = 8 - 4\r
\n" ); document.write( "\n" ); document.write( "x = 4\r
\n" ); document.write( "\n" ); document.write( "Warren is 4 years old now.\r
\n" ); document.write( "\n" ); document.write( "Erin is 3(4) years old now or 12 years old.\r
\n" ); document.write( "\n" ); document.write( "Did you follow?\r
\n" ); document.write( "\n" ); document.write( "For question (1), you are dealing with two equations in two variables.\r
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