document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23406>Question 23406</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you please help me find the intercepts of the equation, and plot the graphs, showing the coordinates where the graphs intersect? \r<BR>\n" );
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document.write( "Here it is:<BR>\n" );
document.write( "2x+y=8<BR>\n" );
document.write( "5x-3y=15\r<BR>\n" );
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document.write( "Thanks so much for your help.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12242 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12242\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SEE THE FOLLOWING EXAMPLE AND FOLLOW THE METHOD TO SOLVE YOUR PROBLEM.COME BACK IF NEEDED<BR>\n" );
document.write( "INTERCEPTS ARE THE DISTANCE FROM ORIGIN TO THE POINT WHERE THE LINE CUTS THE X AXIS (CALLED X INTERCEPT);AND THE Y AXIS (CALLED Y INTERCEPT)ON THE X AXIS Y=0 .SO WE GET X INTERCEPT BY PUTTING Y=0 IN THE GIVEN EQN.FOR EX.IN 2X+Y=8,IF WE PUT Y=0 WE GET 2X=8 OR X=8/2=4.HENCE 4 IS THE X INTERCEPT.<BR>\n" );
document.write( "ON Y AXIS X=0.SO WE GET Y INTERCEPT BY PUTTING X=0 IN THE GIVEN EQN.FOR EX.IN 2X+Y=8,IF WE PUT X=0 WE GET Y=8.HENCE 8 IS THE Y INTERCEPT<BR>\n" );
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document.write( "Solve the system of linear equations by graphing: x+2y=5..<BR>\n" );
document.write( "OR 2Y=5-X..OR Y=(5-X)/2<BR>\n" );
document.write( "                                                  x-y=2...<BR>\n" );
document.write( "OR Y=X-2<BR>\n" );
document.write( "that is the first one <BR>\n" );
document.write( " the second one is:     4x-y=6<BR>\n" );
document.write( "                        3x+y=1\r<BR>\n" );
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document.write( "SOLVE BY GRAPHING MEANS DRAW THE GRAPHS AND FIND THE 2 GRAPHS OF 2 EQUATIONS CUT EACH OTHER .THAT IS THE SOLUTION.LET ME SHOW YOU THE FIRST PROBLEM. THEN YOU CAN DO SECOND PROBLEM THE SAME WAY <BR>\n" );
document.write( "LET X=.........................0......1......2........3.........4......5....ETC.<BR>\n" );
document.write( "Y=(5-X)/2..IN FIRST EQN........5/2....2......3/2......1.........1/2....0...ETC<BR>\n" );
document.write( "Y=(X-2).....IN SECOND EQN.......-2....-1......0........1.........2......3...ETC<BR>\n" );
document.write( "THE GRAPHS WILL LOOK LIKE THIS <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+%285-x%29%2F2%2C+x-2%29+ ALIGN=MIDDLE  ALT=\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+%285-x%29%2F2%2C+x-2%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "WE FIND THAT THE TWO GRAPHS ARE CUTTING AT X=3 AND Y=1.HENCE THAT IS THE SOLUTION..YOU CAN CHECK BACK<BR>\n" );
document.write( "EQN.I.....X+2Y=3+2*1=3+2=5..OK<BR>\n" );
document.write( "EQN.II.....X-Y=3-1=2........OK.<BR>\n" );
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