document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=166092>Question 166092</A>: <I><SPAN STYLE=\"word-break: break-all;\">   My book isn't explaining this very well.  Can you help?<BR>\n" );
document.write( "I'm to solve each system by elimination.<BR>\n" );
document.write( "2(a+b)=94<BR>\n" );
document.write( "4(a-9)=3b-23 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122384 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122384\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2(a+b)=94 <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2a%2B2b=94 ALIGN=MIDDLE  ALT=\"2a%2B2b=94\"   DISABLED_style= \"max-width:90%; height:auto;\" >     distribute<BR>\n" );
document.write( "4(a-9)=3b-23<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4a-36=3b-23 ALIGN=MIDDLE  ALT=\"4a-36=3b-23\"   DISABLED_style= \"max-width:90%; height:auto;\" >  distribute<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4a-3b=13 ALIGN=MIDDLE  ALT=\"4a-3b=13\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "now we have 2a+2b=94<BR>\n" );
document.write( ":::         4a-3b=13<BR>\n" );
document.write( "when you use elimination method in linear equations you multiply one or both equations by a constant that will help eliminate one variable. I n our case we can either multiply the top equation by 4 and the bottom by -2 to eliminate the a variable  or we can multiply the top by 3 and the bottom equation by 2 and get rid of the b variable. I choose the 2nd option\r<BR>\n" );
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document.write( ":          3(2a+2b=94)--->6a+6b=282<BR>\n" );
document.write( ":          2(4a-3b=13)--->8a-6b= 26\r<BR>\n" );
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document.write( "now notice when we add <BR>\n" );
document.write( "these two together that<BR>\n" );
document.write( "the b terms are eliminated<BR>\n" );
document.write( "and we end up with ------- 14a=308---><IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=22 ALIGN=MIDDLE  ALT=\"a=22\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "now we can plug a's value back into either of the original equations solving for b\r<BR>\n" );
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document.write( "----------> 2(22)+2b=94----->44+2b=94--->2b=50---<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=25 ALIGN=MIDDLE  ALT=\"b=25\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "hope that helps explain solving linear equations by elimination  \r<BR>\n" );
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document.write( " </SPAN>\n" );
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