document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=166009>Question 166009</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two cars started from the same place at the same time and traveled in opposite directions. at the end of 6 hours, they were 420 miles apart. if the average rate of the slow car exceeded 1/2 of the average rate of the fast car by 13 mph, find the rate of each car. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122364 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122364\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> fast car = r<BR>\n" );
document.write( "slow car= 1/2r+13<BR>\n" );
document.write( "d=rt<BR>\n" );
document.write( "420=6(r + 1/2r + 13)<BR>\n" );
document.write( "420 = 6r + 3r + 78<BR>\n" );
document.write( "342=9r<BR>\n" );
document.write( "38=r<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "fast car rate = 38<BR>\n" );
document.write( "slow car rate = 1/2(38)(6)<BR>\n" );
document.write( "slow car = 192<BR>\n" );
document.write( ":) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );