document.write( "Question 166061: 10.2 94) sharing cost: The members of a flying club plan to share equally the cost of $200,000 airplane. The members want to find five more people to join the club so that the cost per person will decrease by $2000. How many members are currently in the club? \n" ); document.write( "
Algebra.Com's Answer #122359 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! let P = number of people in the club. \n" ); document.write( "let C = Cost for each person \n" ); document.write( "let T = total cost = 200000 \n" ); document.write( "----- \n" ); document.write( "P*C = 200000 (equation 1) \n" ); document.write( "----- \n" ); document.write( "add 5 people to split the cost and save 2000 per person \n" ); document.write( "----- \n" ); document.write( "(P+5) * (C-2000) = 200000 (equation 2) \n" ); document.write( "----- \n" ); document.write( "you have 2 equations to work with: \n" ); document.write( "----- \n" ); document.write( "multiply out the second equation: \n" ); document.write( "----- \n" ); document.write( "P*C - 2000*P + 5*C - 10000 = 200000 \n" ); document.write( "since P*C equals 200000, then this equation also equals P*C \n" ); document.write( "equation becomes: \n" ); document.write( "P*C - 2000*P + 5*C - 10000 = P*C \n" ); document.write( "subtract P*C from both sides of the equation: \n" ); document.write( "-2000*P + 5*C - 10000 = 0 \n" ); document.write( "add 2000*P + 10000 to both sides of the equation: \n" ); document.write( "5*C = 2000*P + 10000 \n" ); document.write( "divide both sides of the equation by 5: \n" ); document.write( "C = 400*P + 2000 \n" ); document.write( "----- \n" ); document.write( "in equation 1, substitute 400*P + 2000 for C \n" ); document.write( "that equation becomes: \n" ); document.write( "P * (400*P + 2000) = 200000 \n" ); document.write( "multiply out: \n" ); document.write( "400*P^2 + 2000*P = 200000 \n" ); document.write( "divide both sides of equation by 400: \n" ); document.write( "P^2 + 5*P = 500 \n" ); document.write( "subtract 500 from both sides of equation: \n" ); document.write( "P^2 + 5*P - 500 = 0 \n" ); document.write( "solve the quadratic equation: \n" ); document.write( "(P+25) * (P-20) = 0 \n" ); document.write( "roots are: \n" ); document.write( "P = -25 \n" ); document.write( "or \n" ); document.write( "P = 20 \n" ); document.write( "since the number of people can't be negative, P looks like it will be 20. \n" ); document.write( "----- \n" ); document.write( "if P = 20, then P*C = 200000 becomes 20*C = 200000 which make C = 10000. \n" ); document.write( "likes like original number of people is 20 and original investment each is 10000 dollars. \n" ); document.write( "----- \n" ); document.write( "P = number of original members = 20. \n" ); document.write( "C = original investment = 10000. \n" ); document.write( "add 5 new members and total members = 25. \n" ); document.write( "divide 200000 by 25 and you get 8000 investment each. \n" ); document.write( "----- \n" ); document.write( "number of members is 5 more than original (20 + 5 = 25). \n" ); document.write( "amount of investment of each is 2000 less than original investment (10000 - 2000 = 8000). \n" ); document.write( "----- \n" ); document.write( " \n" ); document.write( " |