document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=166066>Question 166066</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the volume of a sphere of radius 4 meters </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122353 by </B><A HREF=/tutors/aboutme.mpl?userid=midwood_trail><B>midwood_trail(310)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=midwood_trail><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122353\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula to use is:\r<BR>\n" );
document.write( "\n" );
document.write( "V = (4/3)pi(r^2), where V = volume measured in cubic units, pi = 3.14 and <BR>\n" );
document.write( "r = radius of 4 meters.\r<BR>\n" );
document.write( "\n" );
document.write( "We plug and chug:\r<BR>\n" );
document.write( "\n" );
document.write( "V = (4/3)(3.14)(4^2)\r<BR>\n" );
document.write( "\n" );
document.write( "V = (4/3) times (3.14) times (16)\r<BR>\n" );
document.write( "\n" );
document.write( "V = 66.99 meters^3\r<BR>\n" );
document.write( "\n" );
document.write( "Did you follow?\r<BR>\n" );
document.write( "\n" );
document.write( "NOTE:  I rounded to two decimal places. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );