document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=166063>Question 166063</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can someone please help:\r<BR>\n" );
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document.write( "Write a cost function for the problem. Assume that the relationship is linear.\r<BR>\n" );
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document.write( "Marginal cost,$40; 70 items cost $3800 to produce\r<BR>\n" );
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document.write( "a. C(x) = 14x + 3800<BR>\n" );
document.write( "b. C(x) = 40x + 1000<BR>\n" );
document.write( "c. C(x) = 40x + 3800<BR>\n" );
document.write( "d. C(x) = 14x + 1000 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122352 by </B><A HREF=/tutors/aboutme.mpl?userid=midwood_trail><B>midwood_trail(310)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=midwood_trail><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Marginal cost,$40; 70 items cost $3800 to produce <BR>\n" );
document.write( "a. C(x) = 14x + 3800<BR>\n" );
document.write( "b. C(x) = 40x + 1000<BR>\n" );
document.write( "c. C(x) = 40x + 3800<BR>\n" );
document.write( "d. C(x) = 14x + 1000\r<BR>\n" );
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document.write( "I assume that C(x) = marginal cost.\r<BR>\n" );
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document.write( "Let x = number of items, which is 70.\r<BR>\n" );
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document.write( "I would say the correct linear equation is choice (c).\r<BR>\n" );
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document.write( "If you want to know the marginal cost, you would replace every x with 70 and simplify your equation.\r<BR>\n" );
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