document.write( "Question 166008: Solution A is 30% alcohol and solution B is 75% alcohol.How much of each should be used to make 100 liters of a solution that is 50% alcohol. \n" ); document.write( "
Algebra.Com's Answer #122338 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .75x+.30(100-x)=.50 *100 \n" ); document.write( ".75x+30-.30x=50 \n" ); document.write( ".45x=50-30 \n" ); document.write( ".45x=20 \n" ); document.write( "x=20/.45 \n" ); document.write( "x=44.444 liters of 75% alcohol is used. \n" ); document.write( "100-44.444=55.556 liters of 30% alcohol is used. \n" ); document.write( "Proof: \n" ); document.write( ".75*44.444+.30*55.556=.50*100 \n" ); document.write( "33.333+16.667=50 \n" ); document.write( "50=50 \n" ); document.write( " |