document.write( "Question 165922: Hi! Pretty please with a cherry on the top would you help me solve this problem! Thank you so much. Appreciate it!\r
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Algebra.Com's Answer #122312 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
Compounded semi-annually. P dollars is invested at annual interest rate r for 1
\n" ); document.write( " year. If the interest is compounded semi-annually, then the polynomial p(1+r/2)^2
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\n" ); document.write( "Rewrite this expression without parenthesis.
\n" ); document.write( "A = p(1+r/2)^2
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\n" ); document.write( "FOIL (1+(r/2))*(1+(r/2)) to get rid of the exponent
\n" ); document.write( "A = p *(1 + $\"2%28r%2F2%29\"$ + $\"r%5E2%2F4\"$ )
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\n" ); document.write( "A = p (1 + r + $\"r%5E2%2F4\"$ ); cancel 2
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\n" ); document.write( "Multiply what's inside the brackets by p
\n" ); document.write( "A = p + pr + $\"%28pr%5E2%29%2F4\"$
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\n" ); document.write( "Evaluate the polynomial if P= $200 and r =10%.
\n" ); document.write( "Substitute for p and r in the above equation
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\n" ); document.write( "A = 200 + 200*.10 + $\"%28200%2A.1%5E2%29%2F4\"$
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\n" ); document.write( "A = 200 + 20 + $\"%28200%2A.01%29%2F4\"$
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\n" ); document.write( "A = 220 + $\"2%2F4\"$
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\n" ); document.write( "A = 220 + .50
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\n" ); document.write( "A = 220.50
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\n" ); document.write( "Check solution on a calc: enter 200*(1+(.1/2))^2 = 220.5 \n" ); document.write( "

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