document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23437>Question 23437</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Prove that if a triangle has two congruent medians, then it is isosceles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12225 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12225\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET ABC be THE TRIANGLE WITH BE AND CF AS THE MEDIANS ,WE ARE GIVEN THAT BE=CF.<BR>\n" );
document.write( "LET BE AND CF MEET AT G THE CENTROID.<BR>\n" );
document.write( "CONSIDER TRIANGLES ECG AND FBG ......WE HAVE <BR>\n" );
document.write( "GE=BE/3=CF/3=GF.....(SINCE MEDIANS ARE TRISECTED AT CENTROID AND BE=CF IS GIVEN)<BR>\n" );
document.write( "GC=2CF/3=2BE/3=GB...(SINCE MEDIANS ARE TRISECTED AT CENTROID AND BE=CF IS GIVEN)<BR>\n" );
document.write( " ANGLE EGC=ANGLE FGB.....(VERTICALLY OPPOSITE ANGLES)<BR>\n" );
document.write( "HENCE THE 2 TRIANGLES ARE CONGRUENT OR IDENTICAL.....<BR>\n" );
document.write( "HENCE BF=CE<BR>\n" );
document.write( "BUT BF=BA/2 AND CE=CA/2...SINCE BE AND CF BEING MEDIANS E AND F ARE MIDPOINTS OF AC AND AB.<BR>\n" );
document.write( "HENCE BA=2BF=2CE=CA<BR>\n" );
document.write( "HENCE THE TRIANGLE IS ISOCELLES </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );