document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165842>Question 165842</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many grams of sugar must be added to 60 grams of a solution that is 32% sugar to obtain a solution that is 50% sugar? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #122242 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=122242\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .32*60+X=.50(60+X)<BR>\n" );
document.write( "19.2+X=30+.5X<BR>\n" );
document.write( "X-.5X=30-19.2<BR>\n" );
document.write( ".5X=10.8<BR>\n" );
document.write( "X=10.8/.5<BR>\n" );
document.write( "X=21.6 GRAMS OF PURE SUGAR IS ADDED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".32*60+21.6=.5(60+21.6)<BR>\n" );
document.write( "19.2+21.6=.5*81.6<BR>\n" );
document.write( "40.8=40.8<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );