document.write( "Question 165843: alice invested a portion of $32,000 at 9% interest and the balance at 11% interest. How much did she invest at each rate if her total income from both investments wa $3200. \n" ); document.write( "
Algebra.Com's Answer #122241 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .11X+.09(32000-X)=3200 \n" ); document.write( ".11X+2880-.09X=3200 \n" ); document.write( ".02X=3200-2880 \n" ); document.write( ".02X=320 \n" ); document.write( "X=320/.02 \n" ); document.write( "X=16,000 INVESTED @ 11%. \n" ); document.write( "32,000-16,000=16,000 INVESTED @ 9% \n" ); document.write( "PROOF: \n" ); document.write( ".11*16,000+.09*16,000=3200 \n" ); document.write( "1760+1440=3200 \n" ); document.write( "3200=3200\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |