document.write( "Question 165843: alice invested a portion of $32,000 at 9% interest and the balance at 11% interest. How much did she invest at each rate if her total income from both investments wa $3200. \n" ); document.write( "
Algebra.Com's Answer #122241 by checkley77(12844)\"\" \"About 
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.11X+.09(32000-X)=3200
\n" ); document.write( ".11X+2880-.09X=3200
\n" ); document.write( ".02X=3200-2880
\n" ); document.write( ".02X=320
\n" ); document.write( "X=320/.02
\n" ); document.write( "X=16,000 INVESTED @ 11%.
\n" ); document.write( "32,000-16,000=16,000 INVESTED @ 9%
\n" ); document.write( "PROOF:
\n" ); document.write( ".11*16,000+.09*16,000=3200
\n" ); document.write( "1760+1440=3200
\n" ); document.write( "3200=3200\r
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